IMO 2024 P1

Determine all real numbers \alpha such that, for every positive integer n, the integer \lfloor \alpha\rfloor + \lfloor2\alpha\rfloor + \cdots + \lfloor n\alpha\rfloor is a multiple of n. (Note that \lfloor z\rfloor denotes the greatest integer less than or equal to z. For example, \lfloor-\pi\rfloor = -4 and \lfloor2\rfloor = \lfloor2.9\rfloor = 2.)

Solution: \alpha is an even integer.

open scoped BigOperators theorem imo_2024_p1 : {(α : ℝ) | ∀ (n : ℕ), 0 < n → (n : ℤ) ∣ (∑ i in Finset.Icc 1 n, ⌊i * α⌋)} = {α : ℝ | ∃ k : ℤ, Even k ∧ α = k} :=
⊢ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋} = {α | ∃ k, Even k ∧ α = ↑k}
⊢ (∀ x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}, x ∈ {α | ∃ k, Even k ∧ α = ↑k}) ∧ {α | ∃ k, Even k ∧ α = ↑k} ⊆ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
/- We introduce a variable that will be used in the second part of the proof (the hard direction), namely the integer `l` such that `2l = ⌊α⌋ + ⌊2α⌋` (this comes from the given divisibility condition with `n = 2`). -/
refine_1⊢ {α | ∃ k, Even k ∧ α = ↑k} ⊆ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
refine_2
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
⊢ x ∈ {α | ∃ k, Even k ∧ α = ↑k}
refine_1
x✝¹:ℝ
y:x✝¹ ∈ {α | ∃ k, Even k ∧ α = ↑k}
x✝:ℕ
x:0 < x✝
S:ℤ
p:Even S ∧ x✝¹ = ↑S
⊢ ↑x✝ ∣ ∑ i ∈ Finset.Icc 1 x✝, ⌊↑i * x✝¹⌋
refine_2
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
⊢ x ∈ {α | ∃ k, Even k ∧ α = ↑k}
refine_1
x✝¹:ℝ
y:x✝¹ ∈ {α | ∃ k, Even k ∧ α = ↑k}
x✝:ℕ
x:0 < x✝
S:ℤ
p:Even S ∧ x✝¹ = ↑S
⊢ ↑x✝ ∣ ∑ i ∈ Finset.Icc 1 x✝, ⌊↑i * x✝¹⌋
/- We start by showing that every `α` of the form `2k` works. In this case, the sum simplifies to `kn(n+1)`), which is clearly divisible by `n`. -/ simp_all[λL:ℕ=>(
x✝¹:ℝ
y:x✝¹ ∈ {α | ∃ k, Even k ∧ α = ↑k}
x✝:ℕ
x:0 < x✝
S:ℤ
p:Even S ∧ x✝¹ = ↑S
L:ℕ
⊢ ⌊↑L * ↑S⌋ = ↑L * S
All goals completed! 🐙
:⌊(L:ℝ)*S⌋=L* S )]
refine_1
x✝¹:ℝ
x✝:ℕ
x:0 + 1 ≤ x✝
S:ℤ
p:S % 2 = 0 ∧ ↑S = ↑S
⊢ ↑(∑ x ∈ Finset.range (x✝.succ - 1), 1 + ∑ x ∈ Finset.range (x✝.succ - 1), x) * S % ↑x✝ = 0
refine_1
x✝¹:ℝ
x✝:ℕ
S:ℤ
x:1 ≤ x✝
p:2 ∣ S
⊢ ↑x✝ ∣ (↑x✝ + ↑x✝ * (↑x✝ - 1) / 2) * S
exact dvd_trans ⟨2+((_:ℕ)-1),
x✝¹:ℝ
x✝:ℕ
S:ℤ
x:1 ≤ x✝
p:2 ∣ S
⊢ (↑x✝ + ↑x✝ * (↑x✝ - 1) / 2) * 2 = ↑x✝ * (2 + (↑x✝ - 1))
linarith[((‹ℕ›:Int)*(‹Nat›-1)).ediv_mul_cancel$ Int.prime_two.dvd_mul.2<|
x✝¹:ℝ
x✝:ℕ
S:ℤ
x:1 ≤ x✝
p:2 ∣ S
⊢ 2 ∣ ↑x✝ ∨ 2 ∣ ↑x✝ - 1
x✝¹:ℝ
x✝:ℕ
S:ℤ
x:1 ≤ x✝
p:2 ∣ S
⊢ 2 ∣ ↑x✝ ∨ 2 ∣ ↑x✝ - 1
All goals completed! 🐙
]⟩ ↑↑(mul_dvd_mul_left @_ (p)) /- Now let's prove the converse, i.e. that every `α` in the LHS is an even integer. We claim for all such `α` and `n ∈ ℕ`, we have `⌊(n+1)*α⌋ = ⌊α⌋+2n(l-⌊α⌋)`. -/
refine_2
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
this:∀ (n : ℕ), ⌊(↑n + 1) * x⌋ = ⌊x⌋ + 2 * ↑n * (l - ⌊x⌋)
⊢ x ∈ {α | ∃ k, Even k ∧ α = ↑k}
this
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
⊢ ∀ (n : ℕ), ⌊(↑n + 1) * x⌋ = ⌊x⌋ + 2 * ↑n * (l - ⌊x⌋)
refine_2
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
this:∀ (n : ℕ), ⌊(↑n + 1) * x⌋ = ⌊x⌋ + 2 * ↑n * (l - ⌊x⌋)
⊢ x ∈ {α | ∃ k, Even k ∧ α = ↑k}
/- Let's assume for now that the claim is true, and see how this is enough to finish our proof. -/
refine_2
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
this:∀ (n : ℕ), ↑⌊x⌋ + (↑l - ↑⌊x⌋) * (↑n * 2) ≤ x * (↑n + 1) ∧ x * (↑n + 1) < ↑⌊x⌋ + (↑l - ↑⌊x⌋) * (↑n * 2) + 1
⊢ x ∈ {α | ∃ k, Even k ∧ α = ↑k}
-- We'll show that `α = 2(l-⌊α⌋)`, which is obviously even.
h
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
this:∀ (n : ℕ), ↑⌊x⌋ + (↑l - ↑⌊x⌋) * (↑n * 2) ≤ x * (↑n + 1) ∧ x * (↑n + 1) < ↑⌊x⌋ + (↑l - ↑⌊x⌋) * (↑n * 2) + 1
⊢ Even ((l - ⌊x⌋) * 2) ∧ x = ↑((l - ⌊x⌋) * 2)
h
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
this:∀ (n : ℕ), ↑⌊x⌋ + (↑l - ↑⌊x⌋) * (↑n * 2) ≤ x * (↑n + 1) ∧ x * (↑n + 1) < ↑⌊x⌋ + (↑l - ↑⌊x⌋) * (↑n * 2) + 1
⊢ x = (↑l - ↑⌊x⌋) * 2
-- To do so, it suffices to show `α ≤ 2(l-⌊α⌋)` and `α ≥ 2(l-⌊α⌋)`.
h.a
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
this:∀ (n : ℕ), ↑⌊x⌋ + (↑l - ↑⌊x⌋) * (↑n * 2) ≤ x * (↑n + 1) ∧ x * (↑n + 1) < ↑⌊x⌋ + (↑l - ↑⌊x⌋) * (↑n * 2) + 1
⊢ x ≤ (↑l - ↑⌊x⌋) * 2
h.a
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
this:∀ (n : ℕ), ↑⌊x⌋ + (↑l - ↑⌊x⌋) * (↑n * 2) ≤ x * (↑n + 1) ∧ x * (↑n + 1) < ↑⌊x⌋ + (↑l - ↑⌊x⌋) * (↑n * 2) + 1
⊢ (↑l - ↑⌊x⌋) * 2 ≤ x
/- To prove the first inequality, notice that if `α > 2(l-⌊α⌋)` then there exists an integer `N > 0` such that `N ≥ 1/(α - 2(l -⌊α⌋))`. By our assumed claim (with `n = N`), we have `⌊α⌋ + 2(l-⌊α⌋)N + 1 > (N+1)α`, i.e. `⌊α⌋ + (2(l-⌊α⌋) - α)N + 1 > α`, and this implies `⌊α⌋ > α`; contradiction. -/ use not_lt.1 (
⊢ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋} = {α | ∃ k, Even k ∧ α = ↑k}
cases exists_nat_ge (1/(x-_)) with|_ N =>nlinarith[ one_div_mul_cancel $ sub_ne_zero.2 ·.ne',9,Int.floor_le x, this N]) /- Similarly, if `α < 2(l-⌊α⌋)` then we can find a positive natural `N` such that `N ≥ 1/(2(l-⌊α⌋) - α)`. By our claim (with `n = N`), we have `(N+1)α ≥ ⌊α⌋ + 2(l-⌊α⌋)N`, i.e. `α ≥ ⌊α⌋ + (2(l-⌊α⌋) - α)N`, and this implies `a ≥ ⌊α⌋ + 1`; contradiction. -/ use not_lt.1 (
⊢ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋} = {α | ∃ k, Even k ∧ α = ↑k}
cases exists_nat_ge (1/_:ℝ)with|_ A=>nlinarith[Int.lt_floor_add_one x,one_div_mul_cancel$ sub_ne_zero.2 ·.ne',this A]) /- Now all that's left to do is to prove our claim `⌊(n + 1)α⌋ = ⌊α⌋ + 2n(l - ⌊α⌋)`. -/
this
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
n✝:ℕ
⊢ ⌊(↑n✝ + 1) * x⌋ = ⌊x⌋ + 2 * ↑n✝ * (l - ⌊x⌋)
-- We argue by strong induction on `n`.
this.ind
x:ℝ
L:x ∈ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋}
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
n✝:ℕ
a✝:∀ m < n✝, ⌊(↑m + 1) * x⌋ = ⌊x⌋ + 2 * ↑m * (l - ⌊x⌋)
⊢ ⌊(↑n✝ + 1) * x⌋ = ⌊x⌋ + 2 * ↑n✝ * (l - ⌊x⌋)
-- By our hypothesis on `α`, we know that `(n+1) | ∑_{i=1}^(n+1) ⌊iα⌋`
this.ind
x:ℝ
l:ℤ
Y:∑ i ∈ Finset.Icc 1 2, ⌊↑i * x⌋ = ↑2 * l
n✝:ℕ
a✝:∀ m < n✝, ⌊(↑m + 1) * x⌋ = ⌊x⌋ + 2 * ↑m * (l - ⌊x⌋)
L:0 < n✝ + 1 → ↑(n✝ + 1) ∣ ∑ i ∈ Finset.Icc 1 (n✝ + 1), ⌊↑i * x⌋
⊢ ⌊(↑n✝ + 1) * x⌋ = ⌊x⌋ + 2 * ↑n✝ * (l - ⌊x⌋)
this.ind
x:ℝ
l:ℤ
n✝:ℕ
Y:⌊x⌋ + ⌊x + x⌋ = 2 * l
a✝:∀ m < n✝, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
L:↑n✝ + 1 ∣ ⌊x + ↑n✝ * x⌋ + ∑ x_1 ∈ Finset.range n✝, ⌊x + ↑x_1 * x⌋
⊢ ↑⌊x⌋ + 2 * (↑n✝ * (↑l - ↑⌊x⌋)) ≤ x + ↑n✝ * x ∧ x + ↑n✝ * x < 1 + (↑⌊x⌋ + 2 * (↑n✝ * (↑l - ↑⌊x⌋)))
this.ind
x:ℝ
l:ℤ
Y:⌊x⌋ + ⌊x + x⌋ = 2 * l
⊢ ∀ (n : ℕ), (∀ m < n, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))) → ↑n + 1 ∣ ⌊x + ↑n * x⌋ + ∑ x_1 ∈ Finset.range n, ⌊x + ↑x_1 * x⌋ → ↑⌊x⌋ + 2 * (↑n * (↑l - ↑⌊x⌋)) ≤ x + ↑n * x ∧ x + ↑n * x < 1 + (↑⌊x⌋ + 2 * (↑n * (↑l - ↑⌊x⌋)))
/- Thus, there exists `c` such that `(n+1)*c = ∑_{i=1}^{n+1} ⌊iα⌋ = ⌊nα+α⌋ + ∑_{i=1}^n ⌊iα⌋`. -/
this.ind.intro
x:ℝ
l:ℤ
Y:⌊x⌋ + ⌊x + x⌋ = 2 * l
A:ℕ
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
c:ℤ
h✝:⌊x + ↑A * x⌋ + ∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c
⊢ ↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)))
this.ind.intro
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
⊢ ↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)))
/- By the inductive hypothesis, `∑_{i=0}^{n-1}, ⌊α+iα⌋ = ∑_{i=0}^{n-1}, ⌊α⌋+2*i*(l-⌊α⌋)`. -/
this.ind.intro
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
⊢ ↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)))
this
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
⊢ ∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
this.ind.intro
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
⊢ ↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)))
this.ind.intro
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this✝:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
this:∑ d ∈ Finset.range A, ↑d = ↑A * (↑A - 1) / 2
⊢ ↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)))
this
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
⊢ ∑ d ∈ Finset.range A, ↑d = ↑A * (↑A - 1) / 2
this.ind.intro
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this✝:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
this:∑ d ∈ Finset.range A, ↑d = ↑A * (↑A - 1) / 2
⊢ ↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)))
this
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this✝:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
this:∑ d ∈ Finset.range A, ↑d = ↑A * (↑A - 1) / 2
⊢ ↑A * (↑A - 1) % 2 = 0
this.ind.intro
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this✝¹:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
this✝:∑ d ∈ Finset.range A, ↑d = ↑A * (↑A - 1) / 2
this:↑A * (↑A - 1) % 2 = 0
⊢ ↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)))
this
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this✝:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
this:∑ d ∈ Finset.range A, ↑d = ↑A * (↑A - 1) / 2
⊢ ↑A * (↑A - 1) % 2 = 0
cases@Int.emod_two_eq A with|_ B
this.inr
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B✝:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this✝:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
this:∑ d ∈ Finset.range A, ↑d = ↑A * (↑A - 1) / 2
B:↑A % 2 = 1
⊢ ↑A * (↑A - 1) % 2 = 0
All goals completed! 🐙
this.ind.intro
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this✝¹:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
this✝:∑ d ∈ Finset.range A, ↑d = ↑A * (↑A - 1) / 2
this:2 ∣ ↑A * (↑A - 1)
⊢ ↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)))
this.ind.intro
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this✝¹:∑ d ∈ Finset.range A, ↑d = ↑A * (↑A - 1) / 2
this✝:2 ∣ ↑A * (↑A - 1)
this:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ↑A * ⌊x⌋ + 2 * ((∑ i ∈ Finset.range A, ↑i) * (l - ⌊x⌋))
⊢ ↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)))
this.ind.intro
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ + ⌊x + ↑A * x⌋ = (↑A + 1) * c
this✝¹:∑ d ∈ Finset.range A, ↑d = ↑A * (↑A - 1) / 2
this✝:2 ∣ ↑A * (↑A - 1)
this:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ↑A * ⌊x⌋ + 2 * ((∑ i ∈ Finset.range A, ↑i) * (l - ⌊x⌋))
⊢ ↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * (↑A * (↑l - ↑⌊x⌋)))
/- Combined with `∑_{i=0}^{n-1},⌊iα+α⌋ = (n+1)c - ⌊nα+α⌋`, we have `⌊nα+α⌋ = (n+1)c - n⌊α⌋ - n(n-1)(l-⌊α⌋)`, so `⌊nα+α⌋ ≥ (n+1)c - n⌊α⌋ - n(n-1)(l-⌊α⌋)` and `⌊nα+α⌋ < (n+1)c - n⌊α⌋ - n(n-1)(l-⌊α⌋) + 1`. Also, since `2*l = ⌊α⌋ + ⌊2α⌋`, we have `2α+⌊α⌋-1 < 2*l ≤ 2α+⌊α⌋.`-/
this.ind.intro
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this✝¹:2 ∣ ↑A * (↑A - 1)
B:∀ (m : ℕ), ↑m < ↑A → ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
h✝:(↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * ↑(↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * ↑(↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
this✝:True
this:True
⊢ ↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
this.ind.intro
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this✝¹:2 ∣ ↑A * (↑A - 1)
B:∀ (m : ℕ), ↑m < ↑A → ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
this✝:True
this:True
h✝:(↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
⊢ ↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
-- We will now show that `c = n*(l-⌊α⌋) + ⌊α⌋`.
this.ind.intro.inl
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this✝¹:2 ∣ ↑A * (↑A - 1)
B:∀ (m : ℕ), ↑m < ↑A → ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
this✝:True
this:True
h✝¹:(↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
h✝:c < ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
S5:⋯ = ⋯
⊢ ↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
this.ind.intro.inr
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this✝¹:2 ∣ ↑A * (↑A - 1)
B:∀ (m : ℕ), ↑m < ↑A → ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
this✝:True
this:True
h✝¹:(↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
h✝:c ≥ ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
S5:⋯ = ⋯
⊢ ↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
this.ind.intro.inl
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this✝¹:2 ∣ ↑A * (↑A - 1)
B:∀ (m : ℕ), ↑m < ↑A → ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
this✝:True
this:True
h✝¹:(↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ≤ x + ↑A * x ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
h✝:c < ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
S5:⋯ = ⋯
⊢ ↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
this.ind.intro.inl
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this:2 ∣ ↑A * (↑A - 1)
h✝¹:c < ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
h✝:(↑A + 1) * ↑c ≤ x + ↑A * x + (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
⊢ ↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
have:(c+1:ℝ)<=A*(l-⌊x⌋)+⌊x⌋+1:=
⊢ {α | ∀ (n : ℕ), 0 < n → ↑n ∣ ∑ i ∈ Finset.Icc 1 n, ⌊↑i * α⌋} = {α | ∃ k, Even k ∧ α = ↑k}
All goals completed! 🐙
this.ind.intro.inl
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this✝:2 ∣ ↑A * (↑A - 1)
h✝¹:c < ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
h✝:(↑A + 1) * ↑c ≤ x + ↑A * x + (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
this:↑c ≤ ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋
⊢ ↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
this.ind.intro.inl.inl
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this✝:2 ∣ ↑A * (↑A - 1)
h✝²:c < ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
h✝¹:(↑A + 1) * ↑c ≤ x + ↑A * x + (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
this:↑c ≤ ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋
h✝:↑c = ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋
⊢ ↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
this.ind.intro.inl.inr
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this✝:2 ∣ ↑A * (↑A - 1)
h✝²:c < ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
h✝¹:(↑A + 1) * ↑c ≤ x + ↑A * x + (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
this:↑c ≤ ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋
h✝:↑c < ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋
⊢ ↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
this.ind.intro.inl.inl
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this✝:2 ∣ ↑A * (↑A - 1)
h✝²:c < ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
h✝¹:(↑A + 1) * ↑c ≤ x + ↑A * x + (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
this:↑c ≤ ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋
h✝:↑c = ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋
⊢ ↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
/- For if `c = n*(l-⌊α⌋) + ⌊α⌋`, then $$` ⌊(n+1)α⌋ = (n+1)c - n⌊α⌋ - n(n-1)(l-⌊α⌋) = (n+1)(n(l - ⌊α⌋) + ⌊α⌋) - n⌊α⌋ - n(n-1)(l-⌊α⌋) = 2n(l-⌊α⌋) + ⌊α⌋ ` as desired. -/ repeat use
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this✝:2 ∣ ↑A * (↑A - 1)
h✝²:c < ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
h✝¹:(↑A + 1) * ↑c ≤ x + ↑A * x + (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
this:↑c ≤ ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋
h✝:↑c = ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋
⊢ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
All goals completed! 🐙
/- Now, we show `c = n*(l-⌊α⌋) + ⌊α⌋` via contradiction split into two cases. First suppose `c ≤ n(l - ⌊α⌋) + ⌊α⌋ - 1`. $$` (n+1)α < (n+1)c - n⌊α⌋ - n(n-1)(l-⌊α⌋) + 1 ≤ (n+1)(n(l-⌊α⌋) + ⌊α⌋ - 1) - n⌊α⌋ - n(n-1)(l-⌊α⌋) + 1 = 2n(l-⌊α⌋) + ⌊α⌋ - n = 2ln - 2n⌊α⌋ + ⌊α⌋ - n ≤ (2α+⌊α⌋)n - 2n⌊α⌋ + ⌊α⌋ - n = nα + n(α-⌊α⌋-1) + ⌊α⌋ n + α. ` contradiction. -/ nlinarith[(
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this✝:2 ∣ ↑A * (↑A - 1)
h✝²:c < ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
h✝¹:(↑A + 1) * ↑c ≤ x + ↑A * x + (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
this:↑c ≤ ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋
h✝:↑c < ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋
⊢ ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋ ≥ ↑c + 1
All goals completed! 🐙
:(A*(l -⌊x⌋):ℝ)+⌊(x)⌋ >=(c)+01),9,Int.add_emod ↑5,Int.floor_le (@x : ℝ),Int.lt_floor_add_one (x:)] /- Next, suppose `c ≥ n(l - ⌊α⌋) + ⌊α⌋ + 1`. $$` (n+1)α ≥ (n+1)c - n⌊α⌋ - n(n-1)(l-⌊α⌋) ≥ (n+1)(n(l-⌊α⌋) + ⌊α⌋ + 1) - n⌊α⌋ - n(n-1)(l-⌊α⌋) = 2n(l-⌊α⌋) + ⌊α⌋ + n + 1 = 2ln - 2n⌊α⌋ + ⌊α⌋ + n + 1 > (2α+⌊α⌋-1)n - 2n⌊α⌋ + ⌊α⌋ + n + 1 = nα + n(α-⌊α⌋) + ⌊α⌋ + 1 > n + α ` contradiction. -/
this.ind.intro.inr
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this:2 ∣ ↑A * (↑A - 1)
h✝¹:c ≥ ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
h✝:(↑A + 1) * ↑c ≤ x + ↑A * x + (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
⊢ ↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋) ≤ x + ↑A * x ∧ x + ↑A * x < 1 + (↑⌊x⌋ + 2 * ↑A * (↑l - ↑⌊x⌋))
nlinarith[(
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
this:2 ∣ ↑A * (↑A - 1)
h✝¹:c ≥ ↑A * (l - ⌊x⌋) + ⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * ↑m * (↑l - ↑⌊x⌋))
h✝:(↑A + 1) * ↑c ≤ x + ↑A * x + (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) ∧ x + ↑A * x < (↑A + 1) * ↑c - (↑A * ↑⌊x⌋ + 2 * (↑A * (↑A - 1) / 2) * (↑l - ↑⌊x⌋)) + 1
⊢ ↑c ≥ ↑A * (↑l - ↑⌊x⌋) + ↑⌊x⌋ + 1
All goals completed! 🐙
:(c:ℝ)>=A*(l-⌊_⌋)+⌊_⌋+1),Int.floor_le x,Int.lt_floor_add_one x]
this
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
this:∑ d ∈ Finset.range A, ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range A, (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
⊢ ↑(A * (A - 1) / 2) = (↑A * ↑A - ↑A * 1) / 2
cases A with|_
this.succ
x:ℝ
l:ℤ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
n✝:ℕ
B:∀ m < n✝ + 1, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range (n✝ + 1), ⌊x + ↑x_1 * x⌋ = (↑(n✝ + 1) + 1) * c - ⌊x + ↑(n✝ + 1) * x⌋
this:∑ d ∈ Finset.range (n✝ + 1), ⌊x + ↑d * x⌋ = ∑ Q ∈ Finset.range (n✝ + 1), (⌊x⌋ + 2 * (↑Q * (l - ⌊x⌋)))
⊢ ↑((n✝ + 1) * (n✝ + 1 - 1) / 2) = (↑(n✝ + 1) * ↑(n✝ + 1) - ↑(n✝ + 1) * 1) / 2
All goals completed! 🐙
use Finset.sum_congr rfl<|
x:ℝ
l:ℤ
A:ℕ
c:ℤ
Y:2 * ↑l ≤ x + x + ↑⌊x⌋ ∧ x + x < 2 * ↑l - ↑⌊x⌋ + 1
B:∀ m < A, ↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)) ≤ x + ↑m * x ∧ x + ↑m * x < 1 + (↑⌊x⌋ + 2 * (↑m * (↑l - ↑⌊x⌋)))
h✝:∑ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = (↑A + 1) * c - ⌊x + ↑A * x⌋
⊢ ∀ x_1 ∈ Finset.range A, ⌊x + ↑x_1 * x⌋ = ⌊x⌋ + 2 * (↑x_1 * (l - ⌊x⌋))
All goals completed! 🐙

The following command shows which axioms the proof relies upon:

'imo_2024_p1' depends on axioms: [propext, Classical.choice, Quot.sound]#print axioms imo_2024_p1
'imo_2024_p1' depends on axioms: [propext, Classical.choice, Quot.sound]

These are the standard built in axioms.